How to try GPIO control

I would like to control GPIO25 with WP76xx module.
I am trying sample code as below URL .

But I can’t confirm start of the program.
(I can’t find this log message “===============CF3 gpio application has started”)log.txt (21.8 KB)

Could you please let me know how to try GPIO control.

It seems you need to “app start” your application.
You can also try this sample

Thanks for your reply.
I tried sample and confirmed start.

Apr 5 02:36:04 swi-mdm9x28-wp user.info Legato: INFO | gpioCf3Demo[12467]/gpioCf3PinComponent T=main | gpioCf3Pin.c _gpioCf3PinComponent_COMPONENT_INIT() 135 | This is sample gpioctl Legato CF3 GPIO app by using le_gpio.api

But code stopped with the following error.

Apr 5 11:36:04 swi-mdm9x28-wp user.emerg Legato: EMR | gpioService[869]/sysfsGpio T=main | gpioSysfsUtils.c gpioSysfs_SetChangeCallback() 596 | Only one change handler can be registered
Apr 5 02:36:04 swi-mdm9x28-wp user.emerg Legato: EMR | gpioCf3Demo[12467]/framework T=main | le_gpioPin22_client.c SessionCloseHandler() 451 | Component for le_gpioPin22 disconnected
Apr 5 11:36:05 swi-mdm9x28-wp user.err Legato: =ERR= | avcDaemon[862]/avcDaemon T=main | assetData.c assetData_RegistrationUpdate() 1946 | unsupported function called.

Please let me know how to resolve.

You can debug the app and see where makes this:

gpioSysfsUtils.c gpioSysfs_SetChangeCallback() 596 | Only one change handler can be registered

You might also try the application here